3y^2-y-2/3y^2+5y+2

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Solution for 3y^2-y-2/3y^2+5y+2 equation: 


y in (-oo:+oo)

3*y^2-((2/3)*y^2)-y+5*y+2 = 0

3*y^2+(-2/3)*y^2-y+5*y+2 = 0

7/3*y^2+4*y+2 = 0

DELTA = 4^2-(2*7/3*4)

DELTA = -8/3

DELTA < 0

y belongs to the empty set

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